Integration Techniques
Master u-substitution, integration by parts, partial fractions, and trigonometric substitutions.
Review: Basic Integration
Power rule: ∫xⁿ dx = x^(n+1)/(n+1) + C (n ≠ -1)
Basic rules:
∫sin(x) dx = -cos(x) + C
∫cos(x) dx = sin(x) + C
∫eˣ dx = eˣ + C
∫(1/x) dx = ln|x| + C
Need techniques for more complex integrals
U-Substitution
Method: Change of variables to simplify integral
Formula: ∫f(g(x))g'(x) dx = ∫f(u) du where u = g(x)
Steps:
- Choose u (usually inner function)
- Find du = u'(x) dx
- Substitute to get integral in u
- Integrate
- Substitute back to x
Example 1: U-Substitution
∫2x(x² + 1)³ dx
Let u = x² + 1
du = 2x dx
Substitute:
= ∫u³ du
= u⁴/4 + C
= (x² + 1)⁴/4 + C
Example 2: Adjusting Constants
∫x cos(x²) dx
Let u = x²
du = 2x dx
x dx = du/2
Substitute:
= ∫cos(u) · (du/2)
= (1/2)∫cos(u) du
= (1/2)sin(u) + C
= (1/2)sin(x²) + C
U-Substitution for Definite Integrals
Two approaches:
- Change limits to u-values
- Substitute back to x, use original limits
Example: Definite Integral
∫[0 to 1] x√(1 + x²) dx
Let u = 1 + x², du = 2x dx
Change limits:
- x = 0: u = 1
- x = 1: u = 2
Integrate:
= (1/2)∫[1 to 2] √u du
= (1/2)∫[1 to 2] u^(1/2) du
= (1/2) · (2/3)u^(3/2)|₁²
= (1/3)[2^(3/2) - 1]
= (1/3)[2√2 - 1]
Integration by Parts
Formula: ∫u dv = uv - ∫v du
Reverse of product rule
Choosing u and dv:
- LIATE rule: Logarithm, Inverse trig, Algebraic, Trig, Exponential
- Choose u from left, dv from right
Example 1: By Parts
∫x eˣ dx
Choose:
- u = x → du = dx
- dv = eˣ dx → v = eˣ
Apply formula:
= x·eˣ - ∫eˣ dx
= x·eˣ - eˣ + C
= eˣ(x - 1) + C
Example 2: Logarithm
∫ln(x) dx
Choose:
- u = ln(x) → du = (1/x) dx
- dv = dx → v = x
Apply:
= x·ln(x) - ∫x·(1/x) dx
= x·ln(x) - ∫1 dx
= x·ln(x) - x + C
Repeated Integration by Parts
Sometimes need to apply by parts multiple times
Example: xe^(-x)
∫x² eˣ dx
First application:
- u = x² → du = 2x dx
- dv = eˣ dx → v = eˣ
= x²eˣ - ∫2x eˣ dx
Second application on ∫2x eˣ dx:
- u = 2x → du = 2 dx
- dv = eˣ dx → v = eˣ
= x²eˣ - [2x eˣ - ∫2eˣ dx]
= x²eˣ - 2x eˣ + 2eˣ + C
= eˣ(x² - 2x + 2) + C
Trigonometric Integrals
Powers of sin and cos
Strategies:
- Odd power: Save one, use identity sin²x + cos²x = 1
- Even powers: Use half-angle formulas
Example: Odd Power
∫sin³(x) dx
Rewrite:
= ∫sin²(x)·sin(x) dx
= ∫(1 - cos²(x))·sin(x) dx
Let u = cos(x), du = -sin(x) dx:
= -∫(1 - u²) du
= -[u - u³/3] + C
= -cos(x) + cos³(x)/3 + C
Example: Even Power
∫cos²(x) dx
Use identity: cos²(x) = (1 + cos(2x))/2
= ∫(1 + cos(2x))/2 dx
= (1/2)∫1 dx + (1/2)∫cos(2x) dx
= x/2 + sin(2x)/4 + C
Trigonometric Substitution
For expressions with √(a² - x²), √(a² + x²), √(x² - a²)
Substitutions:
- √(a² - x²): x = a sin(θ)
- √(a² + x²): x = a tan(θ)
- √(x² - a²): x = a sec(θ)
Example: Trig Substitution
∫√(4 - x²) dx
Let x = 2sin(θ), dx = 2cos(θ) dθ
Substitute:
= ∫√(4 - 4sin²θ) · 2cos(θ) dθ
= ∫2cos(θ) · 2cos(θ) dθ
= 4∫cos²(θ) dθ
= 4 · [θ/2 + sin(2θ)/4] + C
= 2θ + sin(2θ) + C
Back to x:
θ = arcsin(x/2)
sin(2θ) = 2sin(θ)cos(θ) = 2(x/2)√(1-x²/4) = (x/2)√(4-x²)
= 2arcsin(x/2) + (x/2)√(4-x²) + C
Partial Fractions
Decompose rational function into simpler fractions
For: ∫P(x)/Q(x) dx where degree(P) < degree(Q)
Factor denominator, set up partial fractions
Example: Partial Fractions
∫(5x - 1)/(x² - x - 2) dx
Factor: x² - x - 2 = (x - 2)(x + 1)
Decompose:
(5x - 1)/[(x - 2)(x + 1)] = A/(x - 2) + B/(x + 1)
Solve for A, B:
5x - 1 = A(x + 1) + B(x - 2)
x = 2: 9 = 3A → A = 3
x = -1: -6 = -3B → B = 2
Integrate:
= ∫[3/(x - 2) + 2/(x + 1)] dx
= 3ln|x - 2| + 2ln|x + 1| + C
Integration Tables
For complex integrals, use tables or CAS
Common forms catalogued with solutions
Modern approach: Computer algebra systems (Wolfram Alpha, Mathematica)
Choosing the Right Technique
1. Simplify first: Algebra might help
2. Check basic rules: Power rule, standard integrals
3. U-substitution: Look for composition f(g(x))g'(x)
4. By parts: Products of different types (LIATE)
5. Trig identities: Powers of trig functions
6. Trig substitution: Square roots with a² ± x²
7. Partial fractions: Rational functions
8. Technology: When all else fails!
Practice
For ∫x(x²+1)⁵ dx, best method is:
For ∫x ln(x) dx, best method is:
Which substitution for ∫√(9-x²) dx?
∫sin²(x) dx uses what technique?