Solving Trigonometric Equations
Solve equations involving trig functions using algebra, identities, and inverse functions.
Basic Trigonometric Equations
Solve for angle θ when given trig value
Use inverse trig functions:
- sin(θ) = a → θ = sin⁻¹(a)
- cos(θ) = a → θ = cos⁻¹(a)
- tan(θ) = a → θ = tan⁻¹(a)
Important: Find ALL solutions in given interval
Example 1: Simple Sine Equation
Solve: sin(θ) = 1/2 for 0 ≤ θ < 2π
Reference angle: sin⁻¹(1/2) = π/6
Sine positive in Quadrants I and II:
- Q1: θ = π/6
- Q2: θ = π - π/6 = 5π/6
Answer: θ = π/6, 5π/6
Example 2: Cosine Equation
Solve: cos(θ) = -1/2 for 0 ≤ θ < 2π
Reference angle: cos⁻¹(1/2) = π/3
Cosine negative in Quadrants II and III:
- Q2: θ = π - π/3 = 2π/3
- Q3: θ = π + π/3 = 4π/3
Answer: θ = 2π/3, 4π/3
Example 3: Tangent Equation
Solve: tan(θ) = √3 for 0 ≤ θ < 2π
Reference angle: tan⁻¹(√3) = π/3
Tangent positive in Quadrants I and III:
- Q1: θ = π/3
- Q3: θ = π + π/3 = 4π/3
Answer: θ = π/3, 4π/3
Using Algebra First
Isolate trig function before using inverse
Example 1: Addition
Solve: 2sin(θ) + 1 = 0 for 0 ≤ θ < 2π
Isolate sin(θ):
2sin(θ) = -1
sin(θ) = -1/2
Reference angle: π/6
Sine negative in Q3 and Q4:
- Q3: θ = π + π/6 = 7π/6
- Q4: θ = 2π - π/6 = 11π/6
Answer: θ = 7π/6, 11π/6
Example 2: Multiplication and Square Root
Solve: 3cos²(θ) = 1 for 0 ≤ θ < 2π
Solve for cos(θ):
cos²(θ) = 1/3
cos(θ) = ±√(1/3) = ±√3/3
For cos(θ) = √3/3 (positive in Q1, Q4):
- θ = cos⁻¹(√3/3) ≈ 0.955, 2π - 0.955 ≈ 5.328
For cos(θ) = -√3/3 (negative in Q2, Q3):
- θ = π - 0.955 ≈ 2.186, π + 0.955 ≈ 4.097
Answer: Four solutions in [0, 2π)
Quadratic Form Equations
Equations like a·sin²(θ) + b·sin(θ) + c = 0
Treat like quadratic: Let u = sin(θ), solve for u, then find θ
Example 1: Factor
Solve: 2sin²(θ) - sin(θ) = 0 for 0 ≤ θ < 2π
Factor:
sin(θ)(2sin(θ) - 1) = 0
Two cases:
Case 1: sin(θ) = 0
- θ = 0, π
Case 2: 2sin(θ) - 1 = 0 → sin(θ) = 1/2
- θ = π/6, 5π/6
Answer: θ = 0, π/6, 5π/6, π
Example 2: Quadratic Formula
Solve: 2cos²(θ) + 3cos(θ) - 2 = 0
Let u = cos(θ):
2u² + 3u - 2 = 0
Factor: (2u - 1)(u + 2) = 0
Solutions:
- u = 1/2 → cos(θ) = 1/2 → θ = π/3, 5π/3
- u = -2 → cos(θ) = -2 (impossible, |cos| ≤ 1)
Answer: θ = π/3, 5π/3
Using Identities to Solve
Rewrite equation using identities
Example 1: Pythagorean Identity
Solve: sin²(θ) + 2cos(θ) - 2 = 0 for 0 ≤ θ < 2π
Replace sin²(θ):
(1 - cos²(θ)) + 2cos(θ) - 2 = 0
-cos²(θ) + 2cos(θ) - 1 = 0
cos²(θ) - 2cos(θ) + 1 = 0
Factor:
(cos(θ) - 1)² = 0
cos(θ) = 1
Solve:
θ = 0
Answer: θ = 0
Example 2: Double-Angle Identity
Solve: cos(2θ) = cos(θ) for 0 ≤ θ < 2π
Expand cos(2θ):
2cos²(θ) - 1 = cos(θ)
2cos²(θ) - cos(θ) - 1 = 0
Factor:
(2cos(θ) + 1)(cos(θ) - 1) = 0
Case 1: 2cos(θ) + 1 = 0 → cos(θ) = -1/2
- θ = 2π/3, 4π/3
Case 2: cos(θ) - 1 = 0 → cos(θ) = 1
- θ = 0
Answer: θ = 0, 2π/3, 4π/3
Equations with Multiple Angles
Solve for the argument first, then find θ
Example 1: Double Angle
Solve: sin(2θ) = √3/2 for 0 ≤ θ < 2π
Let u = 2θ, solve for u in [0, 4π):
sin(u) = √3/2
u = π/3, 2π/3, 7π/3, 8π/3
Find θ = u/2:
θ = π/6, π/3, 7π/6, 4π/3
Answer: θ = π/6, π/3, 7π/6, 4π/3
Example 2: Different Coefficient
Solve: cos(3θ) = 1/2 for 0 ≤ θ < 2π
Let u = 3θ, solve in [0, 6π):
cos(u) = 1/2
u = π/3, 5π/3, 7π/3, 11π/3, 13π/3, 17π/3
Find θ = u/3:
θ = π/9, 5π/9, 7π/9, 11π/9, 13π/9, 17π/9
Answer: Six solutions
Equations with Different Functions
Convert to single function using identities
Example: Sine and Cosine
Solve: sin(θ) = cos(θ) for 0 ≤ θ < 2π
Divide both sides by cos(θ):
sin(θ)/cos(θ) = 1
tan(θ) = 1
Solve:
θ = π/4, 5π/4
Answer: θ = π/4, 5π/4
Finding All Solutions
General solutions include all rotations
Pattern: θ = θ₀ + 2πn (for sine/cosine)
Pattern: θ = θ₀ + πn (for tangent, shorter period)
Where n is any integer
Example: General Solution
Solve: sin(θ) = 1/2 (all solutions)
Principal solutions: θ = π/6, 5π/6
General form:
θ = π/6 + 2πn or θ = 5π/6 + 2πn
where n is any integer
Degree vs Radian Mode
Always check if answer should be in degrees or radians!
Example: Degrees
Solve: cos(θ) = √2/2 for 0° ≤ θ < 360°
Reference angle: 45°
Cosine positive in Q1, Q4:
θ = 45°, 315°
No Solution Cases
Sometimes equations have no solution
Example 1: Out of Range
Solve: sin(θ) = 2
Range of sine is [-1, 1]
Answer: No solution
Example 2: After Simplification
Solve: 2cos²(θ) + 5 = 0
Isolate:
cos²(θ) = -5/2
Cannot be negative
Answer: No solution
Real-World Applications
Physics: Find times when oscillating object at specific position
Engineering: Solve for phase angles in AC circuits
Astronomy: Determine positions of celestial objects
Signal processing: Find frequencies
Example: Ferris Wheel
Height on Ferris wheel: h(t) = 20sin(πt/30) + 25 meters
When is height 35 m?
Solve:
35 = 20sin(πt/30) + 25
10 = 20sin(πt/30)
sin(πt/30) = 1/2
πt/30 = π/6 + 2πn or 5π/6 + 2πn
t = 5 + 60n or t = 25 + 60n
First times: t = 5 seconds and t = 25 seconds
Practice
Solve: sin(θ) = √3/2 for 0 ≤ θ < 2π
Solve: 2cos(θ) + 1 = 0 for 0 ≤ θ < 2π
Solve: sin²(θ) = 1/4 for 0 ≤ θ < 2π. How many solutions?
Solve: tan(θ) = 1 for 0 ≤ θ < 2π