Polar Coordinates and Parametric Equations
Convert between polar and Cartesian coordinates, graph polar equations, and understand parametric curves.
Polar Coordinate System
Different from Cartesian (x, y)
Polar: Point located by (r, θ)
- r = distance from origin (radius)
- θ = angle from positive x-axis
Advantages: Natural for circular/spiral patterns
Example: Plot Polar Points
(3, π/4): Distance 3, angle 45°
(2, π): Distance 2, angle 180° (on negative x-axis)
(4, 0): Distance 4, angle 0° (on positive x-axis)
Negative r: (r, θ) = (-r, θ + π)
Converting: Polar to Cartesian
Formulas:
x = r cos(θ)
y = r sin(θ)
Derived from right triangle
Example: Polar to Cartesian
(r, θ) = (4, π/3)
Convert:
x = 4 cos(π/3) = 4(1/2) = 2
y = 4 sin(π/3) = 4(√3/2) = 2√3
Cartesian: (2, 2√3)
Converting: Cartesian to Polar
Formulas:
r = √(x² + y²)
θ = arctan(y/x) (adjust for quadrant)
Example: Cartesian to Polar
(x, y) = (3, 3)
Convert:
r = √(3² + 3²) = √18 = 3√2
θ = arctan(3/3) = arctan(1) = π/4
Polar: (3√2, π/4)
Example: Quadrant Adjustment
(-1, 1)
Calculate:
r = √(1 + 1) = √2
θ = arctan(1/-1) = arctan(-1)
Point in quadrant II, so θ = 3π/4
Polar: (√2, 3π/4)
Polar Equations
Relate r and θ
Common forms:
- Circles: r = a
- Lines through origin: θ = constant
- Spirals: r = aθ
- Rose curves: r = a sin(nθ) or r = a cos(nθ)
Example: Circle
r = 4
All points distance 4 from origin
Circle of radius 4 centered at origin
Example: Line
θ = π/6
All points at angle 30°
Line through origin at 30° angle
Rose Curves
r = a sin(nθ) or r = a cos(nθ)
Number of petals:
- n odd → n petals
- n even → 2n petals
Example: Four-Petal Rose
r = 3 cos(2θ)
n = 2 (even) → 2(2) = 4 petals
Maximum r = 3
Limaçons
r = a ± b sin(θ) or r = a ± b cos(θ)
Types depend on ratio a/b:
- a/b < 1: Inner loop
- a/b = 1: Cardioid (heart-shaped)
- 1 < a/b < 2: Dimpled
- a/b ≥ 2: Convex
Example: Cardioid
r = 1 + cos(θ)
a = b = 1, so a/b = 1
Heart-shaped curve
Spiral of Archimedes
r = aθ
As angle increases, distance increases linearly
Example: Spiral
r = θ
At θ = π: r = π
At θ = 2π: r = 2π
Outward spiral
Lemniscate
r² = a² sin(2θ) or r² = a² cos(2θ)
Figure-eight shape
Example: Lemniscate
r² = 9 cos(2θ)
Take square root: r = ±3√(cos(2θ))
Defined when cos(2θ) ≥ 0
Figure-eight centered at origin
Converting Polar Equations
To Cartesian: Use x = r cos θ, y = r sin θ, r² = x² + y²
Example: Polar to Cartesian Equation
r = 4 sin(θ)
Multiply by r:
r² = 4r sin(θ)
x² + y² = 4y
x² + y² - 4y = 0
x² + (y - 2)² = 4
Circle: center (0, 2), radius 2
Parametric Equations
Express x and y as functions of parameter t
x = f(t)
y = g(t)
Advantage: Describe motion/direction along curve
Example: Circle
Parametric equations for circle radius 3:
x = 3 cos(t)
y = 3 sin(t)
As t goes from 0 to 2π, traces circle
Eliminating the Parameter
Convert parametric to Cartesian
Methods:
- Solve for t, substitute
- Use trig identities
- Algebraic manipulation
Example: Eliminate Parameter
x = t + 1, y = 2t - 1
Solve first for t:
t = x - 1
Substitute into second:
y = 2(x - 1) - 1
y = 2x - 3
Cartesian: y = 2x - 3 (line)
Example: Trig Identity
x = cos(t), y = sin(t)
Use identity:
x² + y² = cos²(t) + sin²(t) = 1
Cartesian: x² + y² = 1 (unit circle)
Parametric Curves
Can represent more complex motions
Example: Ellipse
x = 4 cos(t), y = 2 sin(t)
Eliminate parameter:
x/4 = cos(t)
y/2 = sin(t)
(x/4)² + (y/2)² = 1
x²/16 + y²/4 = 1
Ellipse with semi-axes 4 and 2
Cycloid
Path traced by point on rolling circle
Parametric:
x = r(t - sin t)
y = r(1 - cos t)
Famous curve with interesting properties
Applications: Projectile Motion
Horizontal and vertical motion:
x = (v₀ cos α)t
y = (v₀ sin α)t - (1/2)gt²
v₀ = initial velocity, α = launch angle, g = gravity
Example: Projectile
Launch at 30 m/s, 45° angle
Parametric:
x = 30 cos(45°)·t ≈ 21.2t
y = 30 sin(45°)·t - 4.9t² ≈ 21.2t - 4.9t²
Eliminate t to get parabola
Derivatives in Parametric Form
dy/dx = (dy/dt)/(dx/dt)
Use chain rule
Example: Parametric Derivative
x = t², y = t³
Find dy/dx:
dx/dt = 2t
dy/dt = 3t²
dy/dx = 3t²/(2t) = (3/2)t
Applications: Computer Graphics
Bezier curves: Parametric polynomials
Animation: Position as function of time
Game development: Character paths
Polar Area
Area enclosed by r = f(θ) from θ = α to θ = β:
A = (1/2)∫[α to β] r² dθ
Example: Area of Circle
r = 2, full circle (0 to 2π)
Calculate:
A = (1/2)∫[0 to 2π] 4 dθ
= 2∫[0 to 2π] dθ
= 2[θ]₀^(2π)
= 4π
Matches πr² = π(2)² = 4π ✓
Practice
Convert polar (4, π/2) to Cartesian:
Polar equation r = 5 represents:
Eliminate parameter: x = t, y = t². What is y in terms of x?
Rose curve r = 2sin(3θ) has how many petals?